Understanding the bets of racing is not difficult! This section contains all the basics.
WIN A horse bet to win must cross the finish line first.
PLACE A horse bet to place must cross the finish line either first or second. This bet is less risky but also normally pays less than a winning win wager on the same horse.
SHOW Any horse bet to show must finish either first, second, or third. Again, this wager is not as risky but will usually pay less than either a win or place wager on the same horse.
EXACTA The object is to correctly select the first two horses across the finish line in the exact order. For example, if you placed a “23” exacta, the #2 must win the race and the #3 must finish second. This is more difficult than any win, place or show wager but will reward with a higher payoff.
Exactas can be BOXED or WHEELED
QUINELLA The quinella is similar to the exacta. The object is to select the first two horses across the finish line, but in any order. If you placed a “36” quinella, the race must finish either 36 or 63. Either way, as long as the #3 and #6 both finish in the top two, this wager is a winner. The quinella price will on average pay about half of the exacta price. Quinellas can be BOXED or WHEELED.
TRIFECTA The trifecta is basically just an extension of the exacta. The object of a trifecta is to select the first three horses across the finish line in the exact order. An example trifecta would be “236”. The #2 must win, the #3 must finish second, and the #6 must finish 3rd in that exact order. Trifectas can be BOXED or WHEELED.
SUPERFECTA A winning superfecta must select the first four horses across the finish line in the exact order. Superfectas are one of the most difficult wagers to hit but routinely pay hundreds and often thousands of dollars. Superfectas can be BOXED or WHEELED.
DAILY DOUBLE The object is to correctly select which horses will win two consecutive races. Take for example a 63 daily double placed in the first race. The #6 must win the 1st race and the #3 must win the 2nd race. Daily Doubles can be WHEELED.
PICK3 Correctly select the winners of three consecutive races. A Pick3 can be WHEELED.
PICK4 Correctly select the winners of four consecutive races. A Pick4 can be WHEELED.
PICK6 Correctly select the winners of six consecutive races. The Pick6 is the most difficult wager in horse racing. It is also perhaps the most lucrative with payoffs in the 10’s and 100’s of thousands of dollars routinely. A Pick6 can be WHEELED.
If the numbers 1, 2, and 5 are boxed, the combinations of 12, 15, 21, 25, 51, and 52 are covered.
As long as the first two finishers involve the numbers 1, 2, or 5, the boxed ticket is a winner. The more numbers used in a box, the greater the number of possibilities covered. However, the more numbers boxed, the greater the cost to cover the wager.
# of choices

# of combinations

$ amount of bet

Cost of bet

2

2

$1 ($2)

$2 ($4)

3

6

$1 ($2)

$6 ($12)

4

12

$1 ($2)

$12 ($24)

5

20

$1 ($2)

$20 ($40)

6

30

$1 ($2)

$30 ($60)

7

42

$1 ($2)

$42 ($84)

8

56

$1 ($2)

$56 ($112)

9

72

$1 ($2)

$72 ($144)

10

90

$1 ($2)

$90 ($180)

11

110

$1 ($2)

$110 ($220)

12

132

$1 ($2)

$132 ($264)

13

156

$1 ($2)

$156 ($312)

14

182

$1 ($2)

$182 ($364)

A simple rule to remember to compute the cost of a boxed exacta wager would be as follows:
the number of horses to be boxed MULTIPLIED by the next lowest number MULTIPLIED by the dollar amount of the wager. EXAMPLE: A fivehorse exacta box for $3 would be computed 5 (number of horses to be boxed) x 4 (next lowest number) x 3 dollar amount of the wager) = $60.
# of choices

# of combinations

$ amount of bet

Cost of bet

2

1

$2

$2

3

3

$2

$6

4

6

$2

$12

5

10

$2

$20

6

15

$2

$30

7

21

$2

$42

8

28

$2

$56

9

36

$2

$72

10

45

$2

$90

11

55

$2

$110

12

66

$2

$132

13

78

$2

$156

14

91

$2

$182

A simple rule to remember to compute the cost of a boxed quinella wager would be as follows:
number of horses to be boxed MULTIPLIED by the next lowest number DIVIDED by 2 ( because each bet is a combination ) MULTIPLIED by the dollar amount of the wager. EXAMPLE: A fivehorse quinella box for $3 would be computed 5 (number of horses to be boxed) x 4 (next lowest number) DIVIDED BY 2 (because each bet is a combination) x 3 (dollar amount of the wager) = $30.
# of choices

# of combinations

$ amount of bet

Cost of bet

3

6

$1 ($2)

$6 ($12)

4

24

$1 ($2)

$24 ($48)

5

60

$1 ($2)

$60 ($120)

6

120

$1 ($2)

$120 ($240)

7

210

$1 ($2)

$210 ($420)

8

336

$1 ($2)

$336 ($672)

9

504

$1 ($2)

$504 ($1008)

10

720

$1 ($2)

$720 ($1440)

11

990

$1 ($2)

$990 ($1980)

12

1320

$1 ($2)

$1320 ($2640)

13

1716

$1 ($2)

$1716 ($3432)

14

2184

$1 ($2)

$2184 ($4368)

A simple rule to remember to compute the cost of a boxed trifecta wager would be as follows:
the number of horses to be boxed MULTIPLIED by the next lowest number MULTIPLIED by the next lowest number MULTIPLIED by the dollar amount of the wager. EXAMPLE: A fivehorse trifecta box for $3 would be computed 5 (number of horses to be boxed) x 4 (next lowest number) x 3 (next lowest number) x 3 (dollar amount of the wager) = $180.
# of choices

# of combinations

$ amount of bet

Cost of bet

4

24

$1 ($2)

$24 ($48)

5

120

$1 ($2)

$120 ($240)

6

360

$1 ($2)

$360 ($720)

7

840

$1 ($2)

$840 ($1680)

8

1680

$1 ($2)

$1680 ($3360)

9

3024

$1 ($2)

$3024 ($6048)

10

5040

$1 ($2)

$5040 ($10008)

11

7920

$1 ($2)

$7920 ($15840)

12

11880

$1 ($2)

$11880 ($23760)

13

17160

$1 ($2)

$17160 ($34320)

14

24024

$1 ($2)

$24024 ($48048)

A simple rule to remember to compute the cost of a boxed superfecta wager would be as follows:
the number of horses to be boxed MULTIPLIED by the next lowest number MULTIPLIED by the next lowest number MULTIPLIED by the next lowest number MULTIPLIED by the dollar amount of the wager. EXAMPLE: A fivehorse superfecta box for $1 would be computed 5 (number of horses to be boxed) x 4 (next lowest number) x 3 (next lowest number) x 2 next lowest number) x 1 (dollar amount of the wager) = $120.
# of choices

# of combinations

$ amount of bet

Cost of bet

2

2

$1 ($2)

$2 ($4)

3

3

$1 ($2)

$3 ($6)

4

4

$1 ($2)

$4 ($8)

5

5

$1 ($2)

$5 ($10)

6

6

$1 ($2)

$6 ($12)

7

7

$1 ($2)

$7 ($14)

8

8

$1 ($2)

$8 ($16)

9

9

$1 ($2)

$9 ($18)

10

10

$1 ($2)

$10 ($20)

11

11

$1 ($2)

$11 ($22)

12

12

$1 ($2)

$12 ($24)

13

13

$1 ($2)

$13 ($26)

wheeling any number of other horses in multiple combinations to finish in the remaining positions, usually second and third. If the 1 is keywheeled with the 2, 3, and 5, the combinations of 123,
125, 132, 135, 152, and 153 are covered. As long as the 1 is the winner and any combination of the numbers 2, 3, and 5 are second and third, the keywheeled wager is a winner. The more numbers used with the keywheeled selection, the greater the number of possibilities covered. However, the more numbers used, the greater the cost to cover the wager.
# of choices

# of combinations

$ amount of bet

Cost of bet

2

2

$1 ($2)

$2 ($4)

3

6

$1 ($2)

$6 ($12)

4

12

$1 ($2)

$12 ($24)

5

20

$1 ($2)

$20 ($40)

6

30

$1 ($2)

$30 ($60)

7

42

$1 ($2)

$42 ($84)

8

56

$1 ($2)

$56 ($112)

9

72

$1 ($2)

$72 ($144)

10

90

$1 ($2)

$90 ($180)

11

110

$1 ($2)

$110 ($220)

12

132

$1 ($2)

$132 ($264)

13

156

$1 ($2)

$156 ($312)

A simple rule to remember to compute the cost of a keywheeled trifecta wager would be as follows:
the number of horses to be boxed with the keyed selection MULTIPLIED by the next lowest number MULTIPLIED by the dollar amount of the wager. EXAMPLE: A keywheeled trifecta using 4 choices with the keywheeled selection for $2
would be computed 4 (the number of horses boxed with the keywheeled selection) x 3 (next lowest number) x 2 (dollar amount of wager) = $24.
# of choices

# of combinations

$ amount of bet

Cost of bet

3

6

$1 ($2)

$6 ($12)

4

24

$1 ($2)

$24 ($48)

5

60

$1 ($2)

$60 ($120)

6

120

$1 ($2)

$120 ($240)

7

210

$1 ($2)

$210 ($420)

8

336

$1 ($2)

$336 ($672)

9

504

$1 ($2)

$504 ($1008)

10

720

$1 ($2)

$720 ($1440)

11

990

$1 ($2)

$990 ($1980)

12

1320

$1 $2)

$1302 ($2640)

13

1716

$1 ($2)

$1716 ($3432)

A simple rule to remember to compute the cost of a keywheeled superfecta wager would be as follows: the number of horses to be boxed with the keyed selection MULTIPLIED by the next lowest number MULTIPLIED by the next lowest number MULTIPLIED by the dollar amount of the wager. EXAMPLE: A keywheeled superfecta wager using 4 choices with the keywheeled selection for $2 would be computed 4 (number of horses boxed with the keywheeled selection) x 3 (next highest number) x 2 (next highest number) x 2 (dollar amount of the wager) = $48.
Partial wheeling in a daily double bet means using a number of, but not all, selections in one leg (part) of the bet with a number of, but not all, selections in the other leg (part) of the bet. The greater the number of betting choices, the greater the cost of covering the wager.
A simple rule to remember to compute the cost of a wheeled or partial wheeled daily double wager would be as follows: The number of horses selected in Leg (part) A MULTIPLIED by the number of horses selected in Leg (part) B MULTIPLIED by the dollar amount of the wager. EXAMPLE: If 4 choices were selected in Leg (part) A and 6 choices were selected in Leg (part) B and the wager was made for $5, the cost would be computed 4 (selections in Leg A) x 6 (selections in Leg B) x 5 (dollar amount of wager) = $120.
A simple rule to remember to compute the cost of a wheeled or partialwheeled Pick3 wager would be as follows: The number of horses selected in Leg (part) A MULTIPLIED by the number of horses selected in Leg (part) B MULTIPLIED by the number of horses selected in Leg (part) C MULTIPLIED by the dollar amount of the wager. EXAMPLE: If 2 choices were selected in Leg (part) A, 6 choices were selected in Leg (part) B, and 3 choices were selected in Leg (part) C, and the wager was made for $2, the cost would be computed 2 (selections in Leg A) x 6 (selections in Leg B) x 3 (selections in Leg C) x 2 ( dollar amount of wager )= $72.
A simple rule to remember to compute the cost of a wheeled or partialwheeled Pick6 wager would be as follows: The number of horses selected in Leg (part) A MULTIPLIED by the number of horses selected in Leg (part) B MULTIPLIED by the number of horses selected in Leg (part) C MULTIPLIED by the number of horses selected in Leg (part) D MULTIPLIED by the number of horses selected in Leg (part) E MULTIPLIED by the number of horses selected in Leg (part) F MULTIPLIED by the dollar amount of the wager. EXAMPLE: If 2 choices were selected in Leg (part) A, 2 choices were selected in Leg (part) B, 2 choices were selected in Leg (part) C, 2 choices were selected in Leg (part) D, 2 choices were selected in Leg (part) E, and 2 choices were selected in Leg (part) F, and the wager was made for $2, the cost would be computed 2 (selections in Leg A) x 2 (selections in Leg B) x 2 (selections in Leg C) x 2 (selections in Leg D) x 2 (selections in Leg E) x 2 (selections in Leg F) x 2 (dollar amount of wager) = $128.
A simple rule to remember to compute the cost of a wheeled or partialwheeled Pick4 wager would be as follows: The number of horses selected in Leg (part) A MULTIPLIED by the number of horses selected in Leg (part) B MULTIPLIED by the number of horses selected in Leg (part) C MULTIPLIED by the number of horses selected in Leg (part) D MULTIPLIED by the dollar amount of the wager. EXAMPLE: If 2 choices were selected in Leg (part) A, 6 choices were selected in Leg (part) B, 3 choices were selected in Leg (part) C, and 2 choices were selected in Leg (part) D, and the wager was made for $2, the cost would be computed 2 (selections in Leg A) x 6 (selections in Leg B) x 3 (selections in Leg C) x 2 (selections in Leg D) x 2 (dollar amount of wager) = $144.
Wheeling selections in a quinella bet means using all of the remaining selections in combination with a chosen winner in order to cover all combinations of possible finish. The more numbers used, the greater number of possibilities covered. However, the more numbers used, the greater the cost to cover the wager.
A simple rule to remember to compute the cost of a wheeled or partialwheeled quinella bet would be as follows: The number of selections to be used with a chosen winner MULTIPLIED by the dollar amount of the wager equals the cost of the wager. EXAMPLE: If 5 choices are used in combination with a chosen winner and the wager was made for $5, the cost would be computed 5 ( selections ) x 5 ( dollar amount of wager ) = $25.